0=16x^2-22x+112

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Solution for 0=16x^2-22x+112 equation: 



0=16x^2-22x+112

We move all terms to the left:

0-(16x^2-22x+112)=0

We add all the numbers together, and all the variables

-(16x^2-22x+112)=0

We get rid of parentheses

-16x^2+22x-112=0

a = -16; b = 22; c = -112;
Δ = b2-4ac
Δ = 222-4·(-16)·(-112)
Δ = -6684
Delta is less than zero, so there is no solution for the equation

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